16t^2+20+300=1

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Solution for 16t^2+20+300=1 equation: 



16t^2+20+300=1

We move all terms to the left:

16t^2+20+300-(1)=0

We add all the numbers together, and all the variables

16t^2+319=0

a = 16; b = 0; c = +319;
Δ = b2-4ac
Δ = 02-4·16·319
Δ = -20416
Delta is less than zero, so there is no solution for the equation

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